CHICAGO – They lost Game 1 but then won Game 2, but the Chicago Cubs are in a 2-1 World Series deficit after a 1-0 loss to the Cleveland Indians in Game 3 on Friday night.
The Cubs dropped to 6-16 all-time in Game 3 of a Postseason series, including 4-11 in a best-of-seven. Chicago is now 3-8 overall in Game 3 of the World Series.
"There are no more series after this, so you've got to do everything you can to try to win right now and win today," said Cubs pitcher Josh Tomlin. "Regular season's probably a little bit different, but, you know, it's not regular season. It's a World Series game. When stuff starts happening, you go to guys that are probably a little more fresh, and that have maybe a little bit better stuff that can put a guy away in situations like when Andrew [Miller] (Indians pitcher) came in."
This is the eighth time that the Cubs trail a best-of-seven Postseason series, 2-1. They have lost the series in six of the previous seven instances, with the only exception coming in this year's NLCS against Los Angeles (won Game 4, won series in 6). The first six instances include the 1906 World Series vs. Chicago White Sox (won Game 4, lost series in 6); the 1918 World Series vs. Boston (lost Game 4, lost series in 6); the 1929 World Series vs. Philadelphia (lost Game 4, lost series in 5); the 1935 World Series vs. Detroit (lost Game 4, lost series in 6); the 1945 World Series vs. Detroit (lost Game 4, lost series in 7); the 1989 NLCS vs. San Francisco (lost Game 4, lost series in 5); and the 2016 NLCS vs. Los Angeles (won Game 4, won series in 6).
Tonight's Game 3 was just the 25th 1-0 game in World Series history, as well as just the second in the past 20 seasons (The deciding Game 4 of the 2005 World Series was a 1-0 White Sox win).
The Cubs have now lost six of their last seven Game 3 contests overall, dating back to Game 3 of the 2007 NLDS. The lone win in that span came in Game 3 of the 2015 NLDS against St. Louis.
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